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200x^2=1500
We move all terms to the left:
200x^2-(1500)=0
a = 200; b = 0; c = -1500;
Δ = b2-4ac
Δ = 02-4·200·(-1500)
Δ = 1200000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200000}=\sqrt{40000*30}=\sqrt{40000}*\sqrt{30}=200\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200\sqrt{30}}{2*200}=\frac{0-200\sqrt{30}}{400} =-\frac{200\sqrt{30}}{400} =-\frac{\sqrt{30}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200\sqrt{30}}{2*200}=\frac{0+200\sqrt{30}}{400} =\frac{200\sqrt{30}}{400} =\frac{\sqrt{30}}{2} $
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